Why can Python wget report http.client.InvalidURL when using login and password?

Question

Python

The task of downloading logs via http for devices that do not know how to syslog, and so on.
http requires mandatory authorization plain-text

In python, I tried to write the following:

import wget
import yaml

with open('config.yml') as c:
    config = yaml.safe_load(c)

user = str(config['credentials']['user'])
password = str(config['credentials']['password'])
device = atc78-47-msk

url = 'http://'+ user + ':' + password +'@'+ device +'/US/4/config_trunk.log'

wget.download(url)

I get a parsing error, I tried to feed the line - "" http://admin:[email protected]/US/4/config_tr... "" , does not want to accept.

Traceback (most recent call last):
  File "Programs\Python\Python39\lib\http\client.py", line 871, in _get_hostport
    port = int(host[i+1:])
ValueError: invalid literal for int() with base 10: '[email protected]'

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "test.py", line 21, in <module>
    wget.download('http://admin:[email protected]/US/4/config_trunk.log.log')
  File "\venv\lib\site-packages\wget.py", line 526, in download
    (tmpfile, headers) = ulib.urlretrieve(binurl, tmpfile, callback)
  File "Programs\Python\Python39\lib\urllib\request.py", line 239, in urlretrieve
    with contextlib.closing(urlopen(url, data)) as fp:
  File "Programs\Python\Python39\lib\urllib\request.py", line 214, in urlopen
    return opener.open(url, data, timeout)
  File "Programs\Python\Python39\lib\urllib\request.py", line 517, in open
    response = self._open(req, data)
  File "Programs\Python\Python39\lib\urllib\request.py", line 534, in _open
    result = self._call_chain(self.handle_open, protocol, protocol +
  File "Programs\Python\Python39\lib\urllib\request.py", line 494, in _call_chain
    result = func(*args)
  File "Programs\Python\Python39\lib\urllib\request.py", line 1375, in http_open
    return self.do_open(http.client.HTTPConnection, req)
  File "Programs\Python\Python39\lib\urllib\request.py", line 1315, in do_open
    h = http_class(host, timeout=req.timeout, **http_conn_args)
  File "Programs\Python\Python39\lib\http\client.py", line 833, in __init__
    (self.host, self.port) = self._get_hostport(host, port)
  File "Programs\Python\Python39\lib\http\client.py", line 876, in _get_hostport
    raise InvalidURL("nonnumeric port: '%s'" % host[i+1:])
http.client.InvalidURL: nonnumeric port: '[email protected]'

Process finished with exit code 1

PS
Regular Linux wget works fine.

Answer 1

Why use such a strange module?! Use requests - https://docs.python-requests.org/en/latest/
Well, something tells me that you just don't have a 4R-1-ASW device....

import requests
....
r = requests.get('http://' + device +'/US/4/config_trunk.log', auth=('admin', '123456'))