Who will help to deal with the parser ???

Question

Python

import requests
from bs4 import BeautifulSoup

URL = ' https://auto.drom.ru/region25/audi/ '

HEADERS = {
'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 ( KHTML, like Gecko) Chrome/99.0.4844.84 Safari/537.36 OPR/85.0.4341.60',
'accept': '*/*',
}

HOST = ' https://auto.drom.ru '

def get_html(url, params =None):
r = requests.get(url, headers=HEADERS, params=params)
return r

def get_content(html):
soup = BeautifulSoup(html, 'html.parser')
items = soup.find_all('a', {'class': "css-1ctbluq ewrty961"})

cars = []
for item in items:
cars.append({
'title': item.find('span', {'data-ftid': 'bull_title'}).get_text(),
'objec': item.find('div', {'class' : 'css-188tlrp e162wx9x0'}).get_text(),

'price': item.find('span', {'data-ftid': 'bull_price'}).text
})

print(cars)
print(len( cars))

def parce():
html = get_html(URL)
if html.status_code == 200:
get_content(html.text)
else:
print('ERROR')

parce()

[{'title': 'Audi Q7, 2017 ', 'objec': '2.0 l (252 hp), gasoline, 4WD, 67 thousand km ', 'price': '4\xa0000\xa0000\xa0'},

The essence of the question is how to get rid of \xa ???
I've tried different methods and it doesn't work at all.

Answer 1

item.find('span', {'data-ftid': 'bull_price'}).text.replace('\xa0', '')

But it is desirable to add a check that the BS found the required tag and returned the string.