What to do if the program displays the list 2 times when parsing in Python?

Question

Python

I wrote the code according to the guide. When run, it displays the list 2 times, but it needs 1.
Here is my code:

import requests
from bs4 import BeautifulSoup
def parse():
    URL = 'https://my.ranepa.ru/pk/list.php?FT=1&FL=2&FK=&FC=&FB=&FO=&F1=d28d6cfc-36b6-11e6-80ca-005056a02ba9&F2=4ecdef8b-7658-11e9-80f4-005056a03e4f&F3=6e9ce087-c78b-4932-88a5-2628115de4b3&F4=f236a8f4-8f5c-11e9-80f8-005056a03e4f'
    HEADERS = {
        'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.164 Safari/537.36'
        }
    response = requests.get(URL, headers = HEADERS)
    soup = BeautifulSoup(response.content, "html.parser")
    items = soup.findAll('div', class_ = 'bigtable_wrap')
    components = []

    for item in items:
        components.append({
            'title':item.find('tbody').get_text(strip = True)
        })
        for component in components:
            print(component['title'])
parse()

Answer 1

You have the second for loop nested in the first, so the information is displayed several times. Take the second out of the first (write them on the same level)