What is the error in calculating the sum of a sequence of numbers?

Question

C++ / C#

I solve the problem, it is necessary to determine the sum of numbers of a non-empty sequence followed by 0. Calculate the arithmetic and geometric mean. Depends on the sum of numbers, the console shows incorrect counting results, for example, I enter 2 2 0, the compiler answer is: 11271656 .
Grateful for any help!

#include <stdio.h>
#include <conio.h>
#include <math.h>

void main()
{
  int x;
  float sum = 0, prois = 1, sumg, suma, n = 0;

  do
  {
    scanf("%f", &x);
    n = n++;
    sum = sum + x;
    prois = prois*x;
    suma = sum / n;
    sumg = pow(prois, 1 / n);
  } while (x != 0);

  printf("Suma %d", &sum);
  getch();
}

Answer 1

#include <stdio.h>
#include <conio.h>
#include <math.h>

void main()
{
  int n = 0;
  float sum = 0, prois = 1, sumg, suma, x;

  for (;;) {
    scanf("%f", &x);
    if (x == 0)
      break;
    n++;
    sum = sum + x;
    prois = prois*x;
  }
  if (n > 0) {
    suma = sum / n;
    sumg = pow(prois, 1. / n);
  }
  printf("Suma %f", sum);
  getch();
}

Answer 2

Judging by the fact that "int x;" should be "scanf("%d", &x);". The product will always be equal to zero, since it will be multiplied by it first, and only then exit from the loop.

Answer 3

@jcmvbkbc
Thank you for your attention! I'm trying to print the geometric mean, but it's always 1. I can't figure it out.

#include <stdio.h>
#include <conio.h>
#include <math.h>

void main()
{
  int n = 0;
  float sum = 0, prois = 1, sumg, suma, x;

  for (;;) {
    scanf("%f", &x);
    if (x == 0)
      break;
    n++;
    sum = sum + x;
    prois = prois*x;
  }
  if (n > 0) {
    suma = sum / n;
    float step = 1 / n;
    sumg = pow(prois, step);
  }
  printf("Suma %f", sum);
  printf("Cped. arifmetich %f \n ", suma);
  printf("Cped. geometri4eskaya %f", sumg);
  getch();
}