What is the correct way to debug try ... except in Python?

Question

Python

There is some code like this:

try:
        validate(request_json, request_json_schema)
except ValidationError:
        print('Schema not valid!')
        return False

Line

validate(request_json, request_json_schema)

throws an exception everything is fine. We process and work.
But a certain amount of information is also output to the console, where and how specifically the incoming json does not match the required json schema.
In the case of using try ... except verbose output is lost. I don't see it in the debugger either.
What is the course of action in this situation?

Answer 1

try:
    validate(request_json, request_json_schema)
except ValidationError as e:
    print('Schema not valid, и вот почему:')
    print(e)

Answer 2

You can also use `logger`:

import logging

try:
    validate(request_json, request_json_schema)
except ValidationError as e:
    print('Schema not valid, и вот почему:')
    logging.exception(e)