What is compared when comparing an array with a number?

Question

Python

There is an arrayx = [2, 3, 4, 6]

>>> x > 1
True

>>> x < 1
False

At first I thought that 2 non-null elements ( ) were being compared, but then the result in both cases would be grateful if you could explain how it works? True > TrueFalse

Answer 1

In python, this is called a list, it's better to specify.
And the answer to your question is the version of Python, when you compare two data types that are not the same in Python 2 , they are compared lexicographically (is that what it's called?), when two type names are compared alphabetically, i.e. the list type is "list" , the integer type is "int" , the first letter of each word is compared, in the English alphabet letter L comes after i , i.e. the sequence number of the letter L(12) in the alphabet is greater than the sequence number i(9) , so it turns out that list > int (12>9), so in Python 2 the list is larger than a number with type int (or float, decimal, by analogy, but the numeric types int, float, decimal can be successfully compared with each other.)
In Python 3, you will get an error:

>>> x = [2, 3, 4, 6]
>>> x > 1
Traceback (most recent call last):
  File "<pyshell#2>", line 1, in <module>
    x > 1
TypeError: unorderable types: list() > int()