What is a void instance?

Question

CRM

Hello. I saw this thing:

#ifdef NDEBUG
#define LOGGER() (true) ? void() : Logger()
#else
#define LOGGER() Logger()
#endif

And also this:

void foo(void)
{
    return void(); // ?!?!
}

What is it? Why is this? How it works?

Answer 1

Of these two, I only worked with Bitrix, I liked it very much. It works quite fast, there are very useful chips. For example, you can make feedback forms, attach an online chat - very convenient, because the leads will be spinning in one space. Another convenient thing is that there is an internal chat for employees (there is no need to use third-party messengers).
It is convenient to maintain a database of both customers and contractors.
In addition, there are mobile applications.
In my practice, the tasks overlapped completely, so I can’t really talk about the minuses.

Answer 2

#include <iostream>
using namespace std;

int main() {
  cout << int() << endl;
  cout << double(78) << endl;
  
  cout << bool(-1) << endl;
  
  // void r = void();
  // error: void value not ignored as it ought to be
  
  void();
  void(42);
  return 0;
}

Output:
0
78
1
This is syntactic sugar, which can be understood as a built-in type constructor, but in fact it works like a cast to
(int)0, (double)76, (bool)-1 respectively
and the constructor is not called.
Those. when compiling, instead of void(), (void)0 will occur, the result will be void. The foo function returns void because it is "backwards compatible" with the C language.

Answer 3

This is a function that does not return anything.