The error Uncaught TypeError: Cannot read property 'predictions' of undefined takes off how to fix in my case?

Question

JavaScript

Here is the function itself

function makeSearchGoogle() {
    var searchInput = $('.search-input').val();
    if (searchInput) {
        var sessionToken = getSessionToken();
        var string = searchInput + '&sessiontoken=' + sessionToken;
        $.ajax({
            url: 'https://maps.googleapis.com/maps/api/place/autocomplete/json?input=' + string + '&key=AIzaSyCSL1_nsETBMG-E3_7Yk2N7wF5kZikNZZI',
            method: 'get',
            dataType: 'jsonp',
            beforeSend: function () {
                $b.addClass('is-searching');
            },
            complete: function (d) {
                $b.removeClass('is-searching');
                if (typeof d.responseJSON.predictions != 'undefined' && d.responseJSON.predictions.length) {
                    var data = d.responseJSON.predictions;
                    var html = '';
                    var firstId;
                    $.each(data, function (k, v) {
                        if (k < 6) {
                            var parts = v.description.split(', ');
                            var name = parts[0];
                            parts.shift();
                            var other = parts.join(', ');
                            var active = k == 0 ? ' active' : '';
                            firstId = v.place_id;
                            html = html + '<div class="suggestion' + active + '" data-place="' + v.place_id + '">' + ' <b>' + name + '</b>' + (other ? ', ' : '') + other + '</div>';
                        }
                    });
                    $('.suggestions > div').html(html);
                    if (html == '') {
                        $('.suggestions').removeClass('show');
                    } else {
                        if (setIfLoads && firstId && typeof getStarmapDetails != 'undefined') {
                            getStarmapDetails(firstId);
                        }
                        if (makePick) {
                            makePick = false;
                            $('.suggestions').removeClass('show');
                            $('.suggestion').eq(0).click();
                        } else {
                            $('.suggestions').addClass('show');
                        }
                    }
                    setIfLoads = false;
                }
            }
        });
    }
}

Answer 1

responseJSON is a $.ajax property, not the return data. Just print to the console what comes in success (console.log(d)) and see how to parse the result.