Study in C#: Create a strongly typed delegate that returns an anonymous type

Question

.NET

Hey Habr.

Do you want a simple etude in C#?

Let's say we have an anonymous type new{ Name = "aaa", Number = 123 }

How do we make a getAnonimusInstance delegate that returns an anonymous type object?
Those. to compile and run

1. var a = getAnonimusInstance();
2. Console.WriteLine(a.Name);
3. var b = getAnonimusInstance();
4. Console.WriteLine(b.Number == a.Number); //где a и b имеют анонимный тип, описанный выше.

* This source code was highlighted with Source Code Highlighter.

Answer 1

dynamic GetAnonimusInstance()
{
  return new {Name = "aaa", Number = 123};
}

Isn't it?

Answer 2

class Program
{
  static object ReturnAnonymous()
  {
    return new { Name = "aaa", Number = 123 };
  }
  static Func<T> Cast<T>(object obj, T type)
  {
    return () => (T)obj;
  }
  static void Main(string[] args)
  {
    object o = ReturnAnonymous();
    var getAnonimusInstance = Cast(o, new { Name = "", Number = 0 });
    var a = getAnonimusInstance();
    Console.WriteLine(a.Name);
    var b = getAnonimusInstance();
    Console.WriteLine(b.Number == a.Number); //где a и b имеют анонимный тип, описанный выше.
  }
}
* This source code was highlighted with Source Code Highlighter.

Wrote before clarification about 3.5, to adapt laziness.