Stm32 hal adc dma dual channel?

Question

STM

Hello,
I decided to practice STM programming in
any way I can’t start so that the ADC pair mode works humanly for regular channels,


the second ADC shifts the values ​​\u200b\u200bwhere 58 and 7 are the resistor to the ground, the first scan is in the normal position, and then everything is shifted by 1 to the right

volatile uint16_t adc[20] = {0,}; 
void HAL_ADC_ConvCpltCallback(ADC_HandleTypeDef* hadc)
{

        snprintf(trans_str, 127, "\n\n\nADC1 %d %d %d %d %d %d %d %d %d %d\n\nADC2 %d %d %d %d %d %d %d %d %d %d\n", (uint16_t)adc[0], (uint16_t)adc[2], (uint16_t)adc[4], (uint16_t)adc[6], (uint16_t)adc[8],(uint16_t)adc[10],(uint16_t)adc[12],(uint16_t)adc[14],(uint16_t)adc[16], (uint16_t)adc[18],(uint16_t)adc[1], (uint16_t)adc[3], (uint16_t)adc[5], (uint16_t)adc[7], (uint16_t)adc[9],(uint16_t)adc[11],(uint16_t)adc[13],(uint16_t)adc[15],(uint16_t)adc[17], (uint16_t)adc[19]);
    
        HAL_UART_Transmit(&huart3, (uint8_t*)trans_str, strlen(trans_str), 1000);

        adc[0] = 0;
        adc[1] = 0;
        adc[2] = 0;
        adc[3] = 0;
        adc[4] = 0;
        adc[5] = 0;
        adc[6] = 0;
        adc[7] = 0;
        adc[8] = 0;
        adc[9] = 0;
        adc[10] = 0;
        adc[11] = 0;
        adc[12] = 0;
        adc[13] = 0;
        adc[14] = 0;
        adc[15] = 0;
        adc[16] = 0;
        adc[17] = 0;
        adc[18] = 0;
        adc[19] = 0;

}

.....

int main(void){
.....

HAL_ADCEx_Calibration_Start(&hadc1);
  HAL_ADCEx_Calibration_Start(&hadc2);
  HAL_ADC_Start(&hadc2);

while (1)
  {
HAL_ADCEx_MultiModeStart_DMA(&hadc1, (uint32_t*)&adc, 10);
HAL_Delay(5000);
  }
}