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Rotate the image in the canvas so that it fits within the canvas area
I wish you good health, habrovtsy!
I have a problem with image rotation in canvas. It seems to be easy to solve, but I can't find a solution.
I need to rotate an image inside the canvas so that it always fits neatly into its area. The canvas'a size should not change at the same time - the image itself should decrease. In the code below, the image rotates nicely and sits in the center of the canvas, but I don't know how to make it smaller so that it fits neatly.
The image shows exactly what I need (the canvas area is indicated in red).
var canvas=document.getElementById('iconCanvas');//<canvas id="iconCanvas" width="128" height="128"></canvas>
var context=canvas.getContext("2d");
var imgObj=new Image();
imgObj.src='people.jpg';
var width=128;
var height=128;
var angleToRotate=30;
$(imgObj).load(function() {
context.clearRect(0, 0, canvas.width, canvas.height);
var rad = angleToRotate * Math.PI / 180;
context.translate(0 + width / 2, 0 + height / 2);
context.rotate(rad);
//draw the image
context.drawImage(imgObj,width / 2 * (-1),height / 2 * (-1),width,height);
//reset the canvas
context.rotate(rad * ( -1 ) );
context.translate((0 + width / 2) * (-1), (0 + height / 2) * (-1));
});
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I decided on my own in the end. But the solution is tricky. If anyone can come up with something better I'd be grateful :)
$(document).ready(function(){
var canvas=document.getElementById('iconCanvas');//<canvas id="iconCanvas" width="128" height="128"></canvas>
var context=canvas.getContext("2d");
var imgObj=new Image();
imgObj.src='people.jpg';
var iconWidth=128;
var iconHeight=128;
var width=200;
var height=128;
var angleToRotate=30;
$(imgObj).load(function() {
context.clearRect(0, 0, canvas.width, canvas.height);
var rad = angleToRotate * Math.PI / 180;
var newAngle=angleToRotate;
//in case angle is >90
if(newAngle>90 && newAngle<=180){
newAngle=180-newAngle;
}
else if(newAngle>180 && newAngle<=270){
newAngle=270-newAngle;
}
else if(newAngle>270){
newAngle=360-newAngle;
}
context.translate(0 + iconWidth / 2, 0 + iconWidth / 2);
context.rotate(rad);
//draw the image
var newImageWidth=Math.floor((Math.cos((Math.atan(iconWidth/iconHeight)*180/Math.PI)*Math.PI/180)*height)/Math.sin((parseInt(newAngle)+Math.atan(iconHeight/iconWidth)*180/Math.PI)*Math.PI/180));
var newImageHeight=Math.floor((Math.cos((Math.atan(iconWidth/iconHeight)*180/Math.PI)*Math.PI/180)*height)/Math.sin((newAngle+Math.atan(iconHeight/iconWidth)*180/Math.PI)*Math.PI/180));
context.drawImage(imgObj,newImageWidth / 2 * (-1),newImageHeight / 2 * (-1),newImageWidth,newImageHeight);
});
});
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