Regular expressions: only the first one found

Question

Regular Expressions

We have a string:

02 00 00 91 1B 00 00 03 89 02 00 00 91 1B 00 00 03 89 02 00 00 91 1B 00 00 03 89 02 00 00 91 1B 00 00 03 89 02 00 00 0 0 2 00 91 1B 00 00 03 89 02 00 00 91 1B 00 00 03 89 02 00 00 91 1B 00 00 03

Regular expression:

00 00 (\d{2})((\s\S{2}){0,} )\s03\w?

The first "bracket" matches 91

The second should match "1B 00 00", i.e. stop at the first "03" found, but actually stop at the last "03".

As you can see in the source line, the same block is repeated.

How to use a regular expression to ensure that the data of the second bracket stops at the first 03 found. I tried everything I know - it doesn’t work.

The task should be solved only(!) with the help of regular expressions.

Regular expressions are used in javascript.

Answer 1

00 00 (\d{2})((\s\S{2})+?)\s03\w?
+? — 1 or more, ungreedy
Must look for what you need.