PC freezes, what should I do?

Question

Iron

Here such a thing, the PC completely freezes during the game or while watching the video, only the relog helps ...
It so happened that when playing csgo with reduced settings, it does not freeze, but when playing Dota2 it completely refuses not to fall .. .Passed tests maximum CPU temp.,RAM and victoria447 harsh prog rules, didn't reveal any problems...
Windows 7 Service Pack 1 build 7601 (64-bit),
1 x Intel(R) Core(TM)2 Duo CPU E8400 @ 3.00 GHz,
4.0GB RAM,
NVIDIA GeForce 9800 GT, 596GB
HDD

Answer 1

Check for overheating of the video card, for example using FurMark .
Make sure the power supply has enough power. Your video card consumes up to 105 watts, the processor - up to 65, mainly on the 12V bus. That is, the power supply on each of the 12V channels must produce at least 9A, and preferably 12A.

Answer 2

Hmm, what's with the temperature???

Answer 3

Have you tried running Memtest86? Yes, more.

Answer 4

Why doesn't return work? 10 will be displayed on the screen, not 20 (as intended.

because you do not print the result of the function, you print the value of the variable $a, and the result of the execution can be displayed like this:
it is possible if you use pointers, but in your example it makes little sense

Answer 5

You need to pass the argument by reference:

function my_func (&$a){
    $a += 10;
}

$a = 10;

my_func($a);
echo $a;

Answer 6

Why doesn't return work? 10 will be displayed on the screen, not 20 (as intended.

Because a function is a block of code that returns a value, in our case:
So when the function is called

my_func($a)

you need to assign the result to something, for example like this:

$a = 10;
$result_sum = my_func($a);

Answer 7

1.
my_func($a) - you just called the function you passed the argument to. Its result, which is returned by return, you do not use here, so $a does not change for you.
Need
$a=my_func($a);
2. No need to name variables with one letter - you will get confused yourself as soon as there are 10-20 of them in the program. write like this

function my_func ($arg) {
    return $arg + 10;
}
$myVariable = 10;
$result = my_func($myVariable);
echo $result;