Overloading logical operators?

Question

Programming

Tell me, is it possible to implicitly overload all logical operators?

class Product{
private:
    int price;
    string name;
public:
    friend bool operator >(Product a, Product b){
        return a.price > b.price;
    }
};

In the code, the overload of the “greater than” operator, but how to overload the rest without explicitly prescribing?
PS, that is, it is obvious that for equality comparison there will be the following code:

friend bool operator ==(Product a, Product b){
        return a.price == b.price;
    }

Answer 1

you can only define 2 operators < and == , and use namespace std::rel_opswhich has definitions of operators != , > , <= , >= . It?

Answer 2

Take a look at boost/operators.hpp, by the way, maybe this is what you need? It's like std::rel_ops, only much more powerful.

Answer 3

Do you want to use the same code for different operators?