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handless_doc2016-04-13 10:33:32
Do it yourself
handless_doc, 2016-04-13 10:33:32

One of the resistors is heating up. How to fix?

One of the resistors is heated, and strives to smoke and burn out. The second, on the contrary, is completely cold and does not dissipate even the heat that it should.
92def3936dae4e25a6341f703ee872e5.jpg

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6 answer(s)
X
xmoonlight, 2016-04-13
@handless_doc

Option 2:
1. The incoming voltage to the resistor is higher than the allowable one.
2. The resistor broke and it began to heat up.
Check the resistance of the resistor in the off state.
And then turn it on, wait for it to heat up, turn off the power and check again, but watch it.
If the resistance "floats" in the smaller direction, then it's time:
1. Look for the problem of high input voltage (ie the reason for its "breakthrough")
2. And only after that - change the resistor.

C
Cyril, 2016-04-13
@argz

Too fast strong heating may indicate a short circuit.

R
Rsa97, 2016-04-13
@Rsa97

Since the resistor is cold, it means that it dissipates all the heat it generates.
If the resistor heats up, then a large current passes through it. Whether this is normal or not depends on the circuit; it cannot be determined from the photo. There can be both an excess of the supply voltage and an excess of the consumer's power. Based on the power and resistance of the resistor, it is able to withstand a current of 1.58A

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Vladimir Lopatin, 2016-04-13
@VL-endo

From the photo it is very difficult to understand the circuit and its purpose, but check the diode bridges. There are two of them and they are electrically connected to resistors.

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vvs-ts9, 2016-04-13
@vvs-ts9

what about the diode?

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