Multiple awaits in a row?

Question

Node.js

const a = await http.get
const b = await http.get

how will this code be executed?
as far as I know await is "syntactic sugar" and will it still be converted to promises?
does it create 2 promises and fulfill them at the same time or does it create one promise and the second one only when the 1st one resolves?

Answer 1

What does "converted to promises" mean? http.get()in your case, this is the promise.
await is not just syntactic sugar, it is a language construct that blocks any of the following code inside an asynchronous function until the promise passed to it as a parameter has finished executing.
Accordingly, an analogue of your code without using await is

http.get().then(a => http.get().then(b => {
  // Здесь дальнейший код
}))

Example

const p = (resolve, reject) => {
  setTimeout(() => resolve(new Date()), 2000)
}

const syncFn = () => {
  new Promise(p).then(console.log)
  new Promise(p).then(console.log)
}

const asyncFn = async () => {
  const a = await new Promise(p).then(console.log)
  const b = await new Promise(p).then(console.log)  
}

syncFn() 
// Tue Jul 14 2020 15:17:19
// Tue Jul 14 2020 15:17:19

asyncFn()
// Tue Jul 14 2020 15:17:49
// Tue Jul 14 2020 15:17:51