Mass lost by the Sun per second

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Kirill Sidorov2012-03-04 15:30:05

Physics

Kirill Sidorov, 2012-03-04 15:30:05

I understand that the question is not a specialized one, but I think that there are a lot of people with a good knowledge of physics on Habré. Today I helped my younger brother solve problems in physics, I stopped at one and a wild interest ripped me apart. I seem to remember quantum physics and optics quite well, although 4 years have passed, but there is a complete stupor, it is interesting to figure it out.

In the problem, only the total energy flux emitted by the sun is given. What to push off, tell me?

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6 answer(s)

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I2ldo, 2012-03-04
@I2ldo

E=mc^2?

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Kirill Mamaev, 2012-03-04
@r00tGER

We take the mass of the sun at any arbitrary point in time and subtract its mass after one second, the difference will be the answer.

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sielover, 2012-03-04
@sielover

Roughly (for a black body):
$E = \sigma T^4 4\pi R^2t = mc^2$
Temperature 6000 K, time 1 second, radius 700000 km, speed of light and Stefan-Boltzmann constant are known

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Grigory Peretyaka, 2012-03-04
@Peretyaka

The first link in Google:
3. The mass lost by the Sun in 1 s, we determine by applying the law of equivalence of mass and energy
edu.dvgups.ru/METDOC/ENF/PHIZIK/PHIZIK/METOD/STARICHENKO_OPTIKA/WEBUMK/frame/9.htm

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Eternalko, 2012-03-04
@Eternalko

Easily. You need to know the amount of energy that the Sun reproduces in the process of radiation and decay.
That is, how much energy does it release per hour / second? From this, you can calculate the mass loss by E= mc^2 :)

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Grigory Peretyaka, 2012-03-04
@Peretyaka

www.google.com.ua/search?q=Mass%2C+lost+Sun+per+second