Java console input. Why can't I enter a string?

Question

Java

package com.company;
import java.util.Scanner;
public class Main {
  public static void main(String[] args) {
  Scanner in = new Scanner(System.in);
  int y=in.nextInt();
  float x=in.nextFloat();
  in.next();
  String h=in.nextLine();
  System.out.printf("x = %.3f, y =%d, h=%s \n", x,y, h); 
  in.close();
  }
}

1) After entering numbers, the program closes, and h remains unspecified. Please write the correct version of the program and why the above version does not work?
2) why do you need in.close() in which cases to add in which it is not necessary?

Answer 1

After entering the numbers, the program closes, and h remains unspecified. Please write the correct version of the program and why the above version does not work?

Try like this:

package com.company;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int y=in.nextInt();
float x=in.nextFloat();
in.nextLine();
String h = in.nextLine();
System.out.printf("x = %.3f, y =%d, h=%s \n", x,y, h);
in.close();
}
}

Here is the answer to your question:
https://stackoverflow.com/questions/13102045/scann...

why do you need in.close() in which cases to add in which it is not necessary?

When the method is called, the scanner is closed. However, since Scanner implements the Closable interface, you can use Scanner with try with resouces and not explicitly call the close() method.