Is it possible to specify template_name in urls.py?

Question

Django

I have two identical functions in views that output different templates. I want to use one function, but be able to output different templates.

def beats_by_user(request):
    u = User.objects.get(username=request.user)
    pk_list = u.profile.beats_order
    pk_list = ast.literal_eval(pk_list)
    objects = Post.objects.filter(user_beat_id__in=pk_list, author=u)
    objects = dict([(obj.user_beat_id, obj) for obj in objects])
    beats = [objects[user_beat_id] for user_beat_id in pk_list]
    return render(request, 'blog/beat_list.html', {'beats': beats})

def user_profile(request):
    u = User.objects.get(username=request.user)
    pk_list = u.profile.beats_order
    pk_list = ast.literal_eval(pk_list)
    objects = Post.objects.filter(user_beat_id__in=pk_list, author=u)
    objects = dict([(obj.user_beat_id, obj) for obj in objects])
    beats = [objects[user_beat_id] for user_beat_id in pk_list]
    return render(request, 'blog/user_main_profile.html', {'beats': beats})

The urls now looks like this:

url(r'^change-order/$', views.beats_by_user, name='beats'),
    url(r'^my-profile/$', views.user_profile, name='beats'),

Is it possible to specify one function in urls for different URLs, but at the same time display different patterns?

url(r'^change-order/$', views.user_profile, name='beats', template='тут имя шаблона'),
    url(r'^my-profile/$', views.user_profile, name='beats', template='тут имя другого шаблона'),

Or tell me, maybe there is another option not to repeat the same thing in views

Answer 1

Yes, you can .