Is it possible to learn from a function a pointer to a variable where it returns a value, without explicitly specifying it in the O_o parameters?

Question

Qt

Greetings!
In general, subject =)
For example:

int myFunction() 
{
....
*mf = 123;
....
}

void main()
{
int mf = myFunction();
 qDebug()<<"mf"<<mf;
}

I'm interested out of pure interest - I'm ready for hellish crutches and not cross-platform, the MinGW compiler.

Answer 1

Is it possible to learn from a function a pointer to a variable where it returns a value

In general, no. If the return value is a primitive type or a small structure (fitting into 1 - 2 registers, depending on the ABI), then this value is returned in the register(s) and may not be written to memory anywhere at all. If a large structure is returned, then the address where it should be written is passed to the function as an additional hidden parameter.