Is it possible to do an include in a php function?

Question

PHP

Hello, in general, the essence is this, you need to load the module in a php file, first checking the rights, etc., etc.
In the simplest version, it looks like this
index.php

<?php
$v=4;
function load_mod($name)
{
 include 'PATH'.$name.'.php';
}

load_mod('mod_name');
echo $v;
?>

mod_name.php

<?php
$v=5;
?>

Is it possible to solve the problem with scope without packing variables into an array and unpacking them back? Or just include outside the function?
In addition, within a loadable module, you need to have access to classes.

Answer 1

Everything that is in the function disappears when it finishes working, if you do an include in the function, then at the end you need to collect all this and give it to return, then the necessary data can be used further.

Answer 2

You should study the "decorator" pattern) it would help

Answer 3

mod_name.php

<?php
global $v;
$v=5;
?>

Answer 4

Read on topics:
- use in functions (anonymous functions)
- data types in particular pointers a
working example of your code:

<?php
$v=4;
$load_mod=function ($name) use (&$v)
{
 include ''.$name.'.php';
};

$load_mod('mod_name');
echo $v;  // v === 5

But I don't think this is the solution to your problem. Think better about a better architect

Answer 5

I just checked that classes loaded inside the function can be declared outside the function, but this will not work with variables, they must be declared in global visibility.

function LLL()
{
include PRIV.DS.'classes_crm.php';
}

LLL();

$crm_cl = new ShopCRM;