How to uncomment a complex line with Ansible?

Question

Python

Good afternoon!
Given:
file with three lines

--awful.util.spawn('sh -c "sleep 5s && one"')
--awful.util.spawn('sh -c "sleep 5s && two"')
--awful.util.spawn('sh -c "sleep 5s && three"')

Task
Uncomment (remove the first characters --) on the line containing two
My attempt:

- replace:
      dest=/home/{{ desktop_user }}/.config/awesome/rc.lua
      regexp="--awful.util.spawn(\"sh -c \"sleep 5s && two\"')"
      replace="awful.util.spawn(\"sh -c \"sleep 5s && two\"')"

playbook passes without changes
Please help in solving the problem.
Thanks in advance
PS Python don't know
PPS Read the documentation but understood too little.

Answer 1

- replace:
      dest=/home/{{ desktop_user }}/.config/awesome/rc.lua
      regexp="\-\-awful\.util\.spawn\(\'sh\ \-c\ \"sleep\ 5s\ \&\&\ one\"\)"
      replace="awful.util.spawn('sh -c \"sleep 5s && two\"')"

such a line can be prepared like this

import re

print re.escape("""--awful.util.spawn('sh -c "sleep 5s && one")""")

# \-\-awful\.util\.spawn\(\'sh\ \-c\ \"sleep\ 5s\ \&\&\ one\"\)

Answer 2

It’s better to put such files into templates and it’s easy to implement any logic there.