How to truncate the path so that only the filename remains?

Question

Python

In general, I made a png to jpg image converter (and others), in the tkinter window I choose which method and the file selection window opens in the explorer and this is written to the filename variable and I need to somehow trim the path leaving only the file name (because the path is different each time) so that ""im = Image.open(file)"" does not throw an error. I tried everything I could, but alas. A snippet of code if necessary (without trimming options).

filename = askopenfilename()
    for file in filename:
        im = Image.open(file)
        rgb_im = im.convert('RGB')
        rgb_im.save(file.replace("jpg", "png"), quality=95)

Answer 1

for file in filename:will enumerate in file all characters of the string filename.
You just need to pass your filename to open.