How to rewrite code that works in Python 2.7 so that it works in version 3.6?

Question

MySQL

Please help me rewrite the code or point out the key points. The code works fine on version 2.7. But it constantly produces annoying errors on 3.6...

# -*- coding: utf-8 -*-
import urllib2
import urllib
import time
http_url = 'https://api-us.faceplusplus.com/facepp/v3/detect'
key = "please entry YOUR API_KEY"
secret = "please entry YOUR API_SECRET"
filepath = r"YOUR IMAGE PATH"
boundary = '----------%s' % hex(int(time.time() * 1000))
data = []
data.append('--%s' % boundary)
data.append('Content-Disposition: form-data; name="%s"\r\n' % 'api_key')
data.append(key)
data.append('--%s' % boundary)
data.append('Content-Disposition: form-data; name="%s"\r\n' % 'api_secret')
data.append(secret)
data.append('--%s' % boundary)
fr=open(filepath,'rb')
data.append('Content-Disposition: form-data; name="%s"; filename="co33.jpg"' % 'image_file')
data.append('Content-Type: %s\r\n' % 'application/octet-stream')
data.append(fr.read())
fr.close()
data.append('--%s--\r\n' % boundary)

http_body='\r\n'.join(data)
#buld http request
req=urllib2.Request(http_url)
#header
req.add_header('Content-Type', 'multipart/form-data; boundary=%s' % boundary)
req.add_data(http_body)
try:
  #post data to server
  resp = urllib2.urlopen(req, timeout=5)
  #get response
  qrcont=resp.read()
  print qrcont

except urllib2.HTTPError as e:
    print e.read()

Thanks in advance for your help!

Answer 1

https://pynative.com/python-database-connection-po...

Answer 2

You didn't say what kind of error you're getting, but I'm guessing it's
1) SyntaxError on print lines, because print is a function in python3. => Replace all "print ..." with "print(...)"
2) ImportError because urllib2 module is not in python3