How to throw an error when overloading a method?

Question

PHP

Hello everyone again.
There is a certain method that takes 2 arguments as input, but if more than 2 arguments are sent to it, it will still continue to work, how to make it so that it would give an error when overloaded, and how to notice this very overload?

Answer 1

DEMO .

function foo($bar, $baz)
{
  $argsCount = func_num_args();

  if ($argsCount === 2) {
    echo "correct \n";
  } else {
    echo "error: expected 2 arguments, got $argsCount\n";
  }
}

Answer 2

Try to do this - add the third parameter to the method with the default null, and then check in the method if the third parameter is present, then you sent more than 2 ... a crutch, but I hope it helps.

Answer 3

function func( $var1, $var2, ...$params)
{
  if( !empty($params) ) echo 'Передано больше двух параметров!';
}

func(1,2,3); //вызываем

I don't remember exactly what version of PHP it will work with, mine from PHP 5.6

Answer 4

There is a method that takes 2 arguments as input, but if more than 2 arguments are sent to it, it will still continue to work, how to make it so that it would give an error when overloaded, and how to notice this very overload?

You need to use an IDE, then it will immediately be clear that you have made such mistakes.