How to throw a RuntimeException at the line "double weight = 1.0;"?

Question

Java

There is the following method:

public static double weight(Some input params) {
  double weight = 0.0;
  try {
    weight = 1.0;
  } catch(RuntimeException error) {
    // some error handling logic here
    weight = 0.0;
  } 
  return weight;
}

Let me leave behind the scenes why the try block has degenerated into one line during the life of the project, I can only say that there is a set of classes with a template implementation of this method in the form of “try {} catch {}” and the task is to test the code inside the catch block.
Therefore, in fact, the question is, can this be done without changing the code of the method?

Answer 1

I don't really understand what the problem is either. Set a forced throw new RuntimeException();, test the processing logic, and then remove the forced throwing of the exception.
Well, if you want to be absolutely “awesome and inflated”, then replace “weight = 1.0;” to “weight = _dataProvider.getWeightData()”, where in “normal” mode _dataProvider is an instance of the “correct” class (returning normal data), and in test mode it is an instance of a special test class that inherits the same interface, but instead of normal data throwing exceptions.
Just be careful with that, don't end up with " factory factory tool factory " :D

Answer 2

To be honest, it's not clear what the question is? What is the problem?

Answer 3

Maybe change localization?

Answer 4

I finally understood that this is some kind of riddle like “without changing a single character, make the code crash”. It should have been more clearly defined then, otherwise people do not understand.