How to temporarily limit the voltage?

Question

Electronics

Greetings.
In one project I use dc-dc lm2596 (in the assembly on the board, with Ali). According to the datasheet, it has an input voltage of up to 40 volts.
In my case, there may be jumps up to 50 volts.
We need to figure out how to automatically turn off the power supply during such surges.
While the idea came to use a protective diode (suppressor), connected in series to the input. But I don't know what to do with him when the tension rises. There are two options: either it will burn out, or it will break the chain for a while.
Tell me how the suppressor will behave in this case?
Is there another way to protect the lm2596 from a momentary overvoltage at the input?
Thanks in advance.

Answer 1

The suppressor is connected in parallel to the input, not in series.
If these are needles that do not exceed the power of the suppressor, then nothing will happen to him.
You can put more powerful suppressors (2-3 pcs.) Or assembly.
Put a fuse in front of them from the power side.
As in fig. A, B only without resistors. Left entrance, right exit.
You can also lose a few volts on the resistor, just take into account the power.
From short bursts, you can also look at the LC filter.
If it's just an increased supply voltage, then it's easier to find a converter for a higher input voltage.
You can do something like LT4356, but I think not in your case.

Answer 2

LM2576HV

Answer 3

The Schottky diode is set to the desired voltage in order to limit the jumps.
The Schottky diode opens if the voltage is greater than its working voltage and dampens the jump.

Answer 4

You need a TVS diode