How to substitute a variable in {}?

Question

bash

For example
~ $ x=$(seq -f %03g -s, 0 2);echo $x;
000,001,002

How to substitute $x into the echo {A..F}-{ $x } command so that it works like
~ $ echo {A..C}-{000,001,002}
A-000 A-001 A-002 B-000 B-001 B-002 C-000 C-001 C-002

Answer 1

x=$(echo {A..C}-{000..002})
# A-000 A-001 A-002 B-000 B-001 B-002 C-000 C-001 C-002

Answer 2

echo $($(A..F)-$(seq -f %03g -s, 0 2))