Non-greedy regular expressions in Bash?

Question

bash

Help me please.
Perl is easy

Filmix=$(echo "$source_link" | perl -p -e "s|(^.*?filmix.+?)/.*$|\1|")

# I need to truncate the URL if
# the protocols are http or https ,(any)
# domain 2-ur. contains filmix (in the pearl example, it ends in filmix, in principle it will do)
# domain 1-ur. any ,
# up to the form protocol://dom2.dom1 / blah blah blah (without a slash at the end
with sed awk I steamed all day, but I didn’t figure out how.
I think it’s not right, for the sake of one expression, (the whole script on bash), drag pearl courts.

Answer 1

Not sure if I understood you correctly, but:

$ echo 'http//fsdfsd.filmix.com/fsdfsdfsdf/dfsdf?q=ffsdfsdfsdf' | grep -o -P '(^.*filmix.+?)(?=/)'
http//fsdfsd.filmix.com