How to stop a running function (task)?

Question

Node.js

On the server (Node/Express), tasks are running that run at intervals

function testJob (name, timeout) {
  setInterval(() => {
    console.log(name)
  }, timeout)
}

function startUpJobs () {
  Job.find({}).then(jobs => {
    jobs.forEach(job => {
      testJob(job.name, job.timeout)
    })
  })
}

The tasks themselves are stored in Monge, created through the API.
And how to delete a task? For example, I no longer need one of the created tasks. I want to kill him from the GUI. How to implement it? I looked at the bible cronfor Node https://github.com/kelektiv/node-cron there is a way stop()but I don't understand how to identify the right task?

Answer 1

You can try to separate the task code into a separate module, and then run it using spawn() or fork(), while keeping the process id. And to stop the execution of the task, then call process.kill(pid).