How to start execution of one script from another?

Question

Python

Faced such a problem. If one script that runs from this file:

from flask import redirect, send_from_directory, send_file

svc = GenericService(__name__, 'config')
app = svc.get_app()
app.add_api('./openapi/specifications.yml')


@app.app.route('/')
def home():
    return redirect('/v')


@app.app.route('/v1/<path:path>')
def send_frontend(path):
    return send_from_directory('frontend', path)


@app.app.route('/f')
def send_frontend_index():
    return send_file('frontend/index.html', None, False, None, False, 0)


if __name__ == '__main__':
    app.run(debug=True)

Can you please tell me the best way to implement the launch of this script from another file? That is, there is some other script, in the script of which it is sometimes necessary to deploy this script. In which direction to drip?

Answer 1

Here they offer one of 7 options to use
https://stackoverflow.com/a/20749411