How to sort efficiently by the second argument?

Question

Python

Purpose: write a program that will sort people by scores for 3 subjects
Input: first line - surname, second line - scores for 3 subjects separated by a space
Source code

data = []

def insert_data():
    str = input().split(" ")
    name = str[0]
    balli = int(str[1]) + int(str[2]) + int(str[3])
    data.append([name, balli])


for i in range(int(input())):
    insert_data()

data.sort(reverse=True, key=lambda item: item[1])
for item in data:
    print(*item)

How can, after sorting by points, time-efficiently, sort by last name so that the sorting by points is not violated? That is, if there are 2 people Afanasiev 200 and Arefiev 200, first Arefiev should stand, and then Afansiev

Answer 1

To sort by several columns at once, you can use the corresponding element sets in the tuple/list, i.e. change:
data.sort(key=lambda item: (-item[1], item[0]) )

Answer 2

Try using the itemgetter function of the operator module as the argument to the key parameter :

from operator import itemgetter
data.sort(key=itemgetter(1, 0))