How to solve if..else problem in bash?

Question

linux

Hello!
I'm writing a game:

#! /bin/bash
while true
do
        a=$((1 + RANDOM % 10))
        b=$((1 + RANDOM % 10))
        res=$a+$b
        echo -n "$a + $b = "
        read path
        echo ""
        if 
        then
                echo "It's true"
        else
                echo "It's false!!!"
        fi
done

However, it always outputs

It's false!!!

What to do???

Answer 1

By default, bash creates all variables as text, so
res=$a+$b gives you string concatenation, not number addition.
Use explicit arithmetic addition through res=$(( $a + $b ))
or declare all variables in advance as integer through
declare -ia
declare -ib
declare -i res
declare -i path
And ideally, comparison instead of make it numeric

Answer 2

And you look what you have $res
in
res=$(( $a + $b ))