How to simplify this python code?

Question

Python

Hello.
It was sad and lonely, so I wrote a rock-paper-scissors game. In the course of the solution, the following construction arose:

def whowin (first, second):
    if first == 'ножницы'   and second == 'камень':
        print("second win")
    elif first == 'камень'  and second == 'бумага':
        print('second win')
    elif first == 'бумага'  and second == 'ножницы':
        print('second win')

    elif first == 'ножницы' and second == 'бумага':
        print('first win')
    elif first == 'камень'  and second == 'ножницы':
        print('first win')
    elif first == 'бумага'  and second == 'камень':
        print("first win")

I can't help feeling that this solution is a crutch. Please advise how it can be rewritten more correctly.

Answer 1

1 - ножницы
2 - бумага
3 - камень

def whowin (first, second):
    result = (second - first) if abs(second - first) != 2 else -(second - first)
    if result == 0:
        print("ничья")
    elif result > 0:
        print('first win')
    else:
        print('second win')

Без ничьи

def whowin (first, second):
    result = (second - first) if abs(second - first) != 2 else -(second - first)
    print("first win" if result > 0 else "second win")

Answer 2

def whowin(first, second):
    game = {('ножницы', 'камень'): "second win",
        ('камень', 'бумага'): 'second win',
        ('бумага', 'ножницы'): 'second win',
        ('ножницы', 'бумага'):  'first win',
        ('камень',  'ножницы'): 'first win',
        ('бумага'  'камень'): 'first win'}
    print(game[(first, second)])

Наверное, можно еще упростить.

Answer 3

def whowin (first, second):
    if any([
        all([first == 'ножницы',second == 'камень']),
        all([first == 'камень',second == 'бумага']),
        all([first == 'бумага',second == 'ножницы']),
        ]):
        return ('second win')
    elif any([
        all([first == 'ножницы',second == 'бумага']),
        all([first == 'камень',second == 'ножницы']),
        all([first == 'бумага',second == 'камень']),
        ]):
        return ('first win')
    else:
        return None

Answer 4

def whowin(first, second):
    rsp = ('rock', 'scissors', 'paper')
    if rsp.index(first) == rsp.index(second): # also can be first == second
        return 'draw'
    if (rsp.index(first) - rsp.index(second)) % 3 == 1:
        return 'second'
    else:
        return 'first'