How to send an image using socket?

Question

Python

Evenings. So, I took an interest in sockets in python. Wanted to send a picture.
Looked at the code on the Internet - does not fit. I tried to write myself based on what I had already seen.
server

import socket
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
sock.bind(("", 9999))
data, addr = sock.recvfrom(1024)
print(data.decode(), addr)
with open("mi.png", "rb") as mifile:
    midata = mifile.read(1024)
    while midata:
        sock.sendto(midata, addr)
        midata = mifile.read(1024)
print("Done.")
sock.close()

client

import socket
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
sock.connect(("localhost", 9999))
sock.send("Hello, Server!".encode())
with open("mi2.png", "ab") as mifile:
    data = sock.recv(1024)
    while data:
        mifile.write(data)
        data = sock.recv(1024)
print("Done.")
sock.close()

The first message is sent from the client side, the server shuts down, but no data is written. My first solution was:
server

with open("mi.png", "rb") as mifile:
    midata = mifile.read()
    while midata:
        sock.sendto(midata, addr)

client

with open("mi2.png", "wb") as mifile:
    mifile.write(sock.recv(1024))

In this case, the file was saved, but was damaged (The weight of the original file was saved, but the disk space was taken up by 0 ) . In the second case, nothing is recorded at all (0 what is there, what is there.) .

How can you decide?

Answer 1

Well, for starters, learn the difference between TCP (SOCK_STREAM) and UDP (SOCK_DGRAM).
In the latter case, you DO NOT GUARANTEE either the fact of delivery of messages, or their correct order, and there are restrictions on the size of the message. Also the server has no idea when the client has finished sending messages.
So it's better to figure out how to establish (and correctly close!) a TCP connection and rewrite the script for it.