How to select records through where the relation has a condition?

Question

Laravel

Greetings, I read the documentation, but I did not find what I needed.
There are 2 tables: The first has a link to the second.
Example (type_id | int:255) -> Types (id | int:255, name | string)
Need to pull all records from Example where type_id is equal to id from type table where name = 'example'.
That is, in the type table we are looking for the name 'example', it will have id == 3, for example. And already Example is looking for type_id == 3.
The question itself is how to do this using the Example model and its relations.

Example::where('types', function ($query) {
            $query->select('id')
                ->from(with(new Type())->getTable())
                ->where('name', 'пример');
        })->get();

That is, in this case, it can be described in this way. But I would like to find a beautiful option with an attitude.

Answer 1

// types - это отношение один ко многим

$rs = Example::whereHas('types', function($q) {
    $q->where('name', 'пример');
})->get();

Documentation with examples