How to see the class to which the method belongs?

Question

Python

In general, I want to figure out how janga works when it calls CBV, what classes it refers to, what it requests and I want to display the "class -> method / attribute" list, I
try to do this

def __getattribute__(self, *args, **kwargs):
        (string,) = args
        if ('__class__' != string):
            print(self.__class__.__name__, ' ', *args)
        return super().__getattribute__(*args, **kwargs)

It outputs only the name of the parent, how can you see which class which method belongs to?
UPD2: Who cares here is the solution

def __getattribute__(self, *args, **kwargs):
        (string,) = args
        if '__class__' != string:
            from inspect import isfunction
            if hasattr(self.__class__, string):
                if isfunction(getattr(self.__class__, string)):
                    print(getattr(self.__class__, string).__qualname__, ' ', *args, **kwargs)
        return super().__getattribute__(*args, **kwargs)

Answer 1

When I dealt with CBV, I used this site . There is very clearly all the links and code can be traced.

Answer 2

Is it not fate to look at the source codes?
https://github.com/django/django/tree/master/djang...
In views, everything is as simple as two fingers.

Answer 3

Output self.__class__ .