How to search and display words in a string?

Question

linux

Good day, dear users!
I ask for help in solving such a problem:
There is a dump.xml file, where there are links to sites of interest to me (Many links).
The problem is that there are also not so much links, but also a bunch of other "uninteresting in my case" information.
I would like to "pull out" only the links themselves from the file, and I would like to do this with a simple tool - the Linux command line.
It's pretty simple, just write a regular expression and grep the file. But in my case the file consists of only one line. And all these links, as well as other information I do not need, are all in one line. Therefore, egrep is useless here, because in fact, it displays the contents of the entire file, because grep - displays a line that matches the pattern.
Maybe there is a special key in egrep (although I read man and did not find it), or another command is suitable for this task?

Answer 1

man grep:
-o, --only-matching
Prints only the matching part of the lines.

Answer 2

If this file is in xml format, you need to use an xpath query (or even an xslt transform) to retrieve the required information.
XML to process with regular expressions - mauvais ton and incorrectly.