How to run a task first?

Question

gulp.js

There is a task:
gulp.task('build', gulp.parallel('prettier', 'webpack', 'eslint', 'csso', 'postcss', 'icons', 'nunjucks', 'images'));

It runs all tasks in parallel/simultaneously. How to make it so that the very first one processes prettier and after it, the rest are already launched in parallel? i.e. the rest wait until prettier is completed and only then start to execute simultaneously.