How to round the received value from the analog input to tenths?

Question

Arduino

How to round the received value from the analog input to tenths?
The value is displayed on the LCD display, the value must be displayed in tenths.

#include <LiquidCrystal.h>
#include <math.h>
#define analogPin  A0
#define beta 4090
LiquidCrystal lcd(3,4,8,9,10,11);
double termo = 0;
float voltage;
int temp;

 void setup()
 {
 lcd.begin(16,2);
 lcd.print("Temperature:");
 lcd.setCursor(6,1);
 lcd.print("C");
 }
void loop()
{ 
  long a = analogRead(analogPin);
  // расчет по формуле
  float termo = beta /(log((1025.0 * 10 / a - 10) / 10) + beta / 298.0) - 273.0;
  delay(100);
  lcd.setCursor(0,1);
  lcd.print(termo);
}

Answer 1

char str_temp[6];

/* 4 is mininum width, 1 is precision; float value is copied onto str_temp*/
dtostrf(termo , 4, 1, str_temp);
sprintf(temperature,"%s F", str_temp);

Answer 2

And that doesn't work?
lcd.print(termo, 1);