How to rewrite the script to work with three forms?

Question

JavaScript

There is a script.
works with two forms... I just can't rewrite it to work with three forms...

jQuery(document).ready(function ($) {
    // Display form from link inside a popup
  $('#pop_login, #pop_signup').live('click', function (e) {
        formToFadeOut = $('form#register');
        formtoFadeIn = $('form#login');
        if ($(this).attr('id') == 'pop_signup') {
      formToFadeOut = $('form#login');
            formtoFadeIn = $('form#register');
      
        }

  
        formToFadeOut.fadeOut(500, function () {
            formtoFadeIn.fadeIn();
        })
    
        return false;
    });


    // Show the login/signup popup on click
    $('#show_login, #show_signup).on('click', function (e) {
        $('body').prepend('<div class="login_overlay"></div>');
        if ($(this).attr('id') == 'show_login') 
      $('form#login').fadeIn(500);
        else
      $('form#recover').fadeIn(500);
    
        e.preventDefault();
    });

  // Perform AJAX login/register on form submit
  $('form#login, form#register').on('submit', function (e) {
        if (!$(this).valid()) return false;
        $('p.status', this).show().text(ajax_auth_object.loadingmessage);
    action = 'ajaxlogin';
    username = 	$('form#login #username').val();
    password = $('form#login #password').val();
    email = '';
    security = $('form#login #security').val();
    if ($(this).attr('id') == 'register') {
      action = 'ajaxregister';
      username = $('#signonname').val();
        	email = $('#email').val();
        	security = $('#signonsecurity').val();	
    }
    
    ctrl = $(this);
    $.ajax({
            type: 'POST',
            dataType: 'json',
            url: ajax_auth_object.ajaxurl,
            data: {
                'action': action,
                'username': username,
                'password': password,
        'email': email,
                'security': security
            },
            success: function (data) {
        $('p.status', ctrl).text(data.message);
        if (data.loggedin == true) {
                    document.location.href = ajax_auth_object.redirecturl;
                }
            }
        });
        e.preventDefault();
    });
  
  // Client side form validation
    if (jQuery("#register").length) 
    jQuery("#register").validate();
    else if (jQuery("#login").length) 
    jQuery("#login").validate();
});

Who will tell you how to do it? *)

Answer 1

pass the form selector inside the handler, pass requests with data objects to Ajax.
P.S. live method - depricated - can be used instead of .live('click' and .on('click' - .click()

Answer 2

The power of the charger is not enough under heavy load, the voltage drops below what is necessary for charging.

Answer 3

Home charger? It may not have enough power under load.

Answer 4

There is a simple option - broken power connector. Or what they stick in, or what they stick into. According to the description, it is very similar!