How to return the result of the decorator?

Question

Python

The situation is this, it was necessary to return the result of the work of the following decorator from the Pyrogram module:
@app.on_message(filters.text)
def message(client, message):
msg = message.text
return msg
However, it is not possible to do this according to the principle a = message() , since I do not need to pass any arguments to this function, because they already appear, as I understand it, as a result of the work of the on_message decorator. I would really appreciate if someone could suggest what I can do about this.

Answer 1

Well, for starters, what do you understand by "the result of the decorator's work"?
The result of the decorator is a function, if anything!
Those. the code

@app.on_message(filters.text)
def message(client, message):
    msg = message.text

Almost equivalent to code

decorator = app.on_message(filters.text)

def message(client, message):
    msg = message.text
# функция заменяется на результат работы декоратора - на ту же самую или другую функцию
message = decorator(message)

And what the decorator returns, as well as what else it does with the function, is its business.
Moreover, in your case, I strongly suspect that the message() function should not return anything. If you need to store the entered message, use global variables.