How to render a view along the same route depending on a condition?

Question

Laravel

Here is my router code

Route::group(['middleware' => 'guest'], function () {
    Route::get('/', function () {
        return view('layouts/login');
    })->name('login');
});

Route::group(['middleware' => 'auth'], function () {
    Route::get('/', function () {
        return view('index');
    })->name('index');
    Route::get('/', function () {
        return view('layouts/main');
    })->name('main');
    Route::get('/profile', function () {
        return view('layouts/profile');
    })->name('profile');
    Route::get('/exchange', function () {
        return view('layouts/exchange');
    })->name('exchange');
});

If I use in the guest group instead of the route "/" any other "login",'"auth" and so on. then everything is fine, but if you leave "/", then it will crash. It is Route [login] not defined.
important to use the main page for login.

Answer 1

First, learn how to create controllers.
Then read about Auth and how to find out if the user is currently logged in or not, depending on this, give different templates, and do not create "2 routes per link" because. it's impossible.

Answer 2

if (auth()->guest()) {
Route::group(['middleware' => 'guest'], function () {
    Route::get('/', function () {
        return view('layouts/login');
    })->name('login');
});
} else {

Route::group(['middleware' => 'auth'], function () {
    Route::get('/', function () {
        return view('index');
    })->name('index');
    Route::get('/', function () {
        return view('layouts/main');
    })->name('main');
    Route::get('/profile', function () {
        return view('layouts/profile');
    })->name('profile');
    Route::get('/exchange', function () {
        return view('layouts/exchange');
    })->name('exchange');
});
}

Answer 3

Why can't you take authentication out of the box? You can even top it off if you need to. Why be so perverted?