How to rename folders using i+100 pattern?

Question

linux

There are many folders named 200, 201,202... You need to rename them to 300, 301,302 and so on. How can this be done with bash?

Answer 1

mkdir tmp/
mv {200..100500} tmp/
for i in {200..100500}; do mv tmp/$i ./$(expr $i + 100); done
rm tmp/

Answer 2

I didn’t understand what bash has to do with it and why there are some loops for this, perl scripts in 10 (O_o) lines, etc., if there are 100500 one-line solutions with different standard external utilities. And in this case, you can generally rename it simply with the rename command:

rename 2 3 2??

Answer 3

If perl suits, then here is a program for renaming, the first digit in the name increases by one.
The first parameter is a directory, like
rename.pl /path/to/dir

#!/usr/bin/perl

$dir = $ARGV[0];
exit if ( !-d $dir );
opendir DIR, $dir;
for $old ( grep -d "$dir/$_", readdir DIR ) {
  next unless ( $old =~ /^(\d)(\d+)/ );
  $new = ( $1 + 1 )."$2";
  rename( "$dir/$old", "$dir/$new" );
}

Answer 4

Tell me, how to batch rename files so that the last character is not affected. For example, you need to rename filname[x] to new[x]