How to remove square brackets and content using regular expressions?

Question

Python

there is a line from which you need to remove the square brackets and their contents, if inside the brackets there is an integer
I try like this:

import re
s = "one [two] three [1] [2]"
print(re.sub(r'/\[.*?\]/', '', s))

I get the same string as output:
"one [two] three [1] [2]"

Answer 1

re.sub('[\d]', '', s)
For the 128th time, I promise myself to learn regular expressions. And every time I think - "Yes, no, no longer needed!"

Answer 2

>>> import re
>>> 
>>> s = "one [two] three [1] [2]"
>>> 
>>> re.sub(r'\[\d+\]', '', s)
'one [two] three  '
>>>

Answer 3

s = "one [two] three [1] [2]"
print(re.sub('\[|\]', '', s))