How to remove duplicates in a two-dimensional array by replacing?

Question

Python

The array list
[ ['0.00221980', '0.00000000'] , ['0.00222220', '16.05000000'], ['0.00222230', '60.78000000'], ['0.00222240', '0.00000000'] , ['2.5000'] , ['2.50 0.00000000'] , ['0.00222260', '25.87000000'], ['0.00222270', '67.41000000'], ['0.00222280', '18.61000000'], ['0.00228000', '1880.0'i]
should be removed from it ]
, ['0.00222280', '18.61000000'] ,['0.00228000', '1882.18000000'] ]
more
array ['0.00222280', '0.00000000'], ['0.00228000', '0.00000000'], ['0.00222264', '31.17000000']
there is a kind of replacement if with 0 it deletes
[ ['0.00222220', '16.05000000'], ['0.00222230', '60.78000000'], ['0.00222260', '25.87000000'], ['0.00222270', '67.4'000000] ]
and adds which is normal
[ ['0.00222220', '16.05000000'], ['0.00222230', '60.78000000'], ['0.00222260', '25.87000000'], ['0.00222270', '67.41000000'2], ['2.06000'2 , '31.17000000'] ] and
sorts in ascending order by 1 number
if there is already an incoming value, then leave which is included
in python.

Answer 1

Judging by the description, from both arrays it is necessary to remove all elements that have the same 1st value in the 2nd '0.00000000'. Then we can do this (a, b are our arrays):

# находим все значения с нулями
nn = [x[0] for x in a+b if x[1] == '0.00000000']
# фильтруем суммарный массив по этим значениям
d = [x for x in a+b if x[0] not in nn]
# в конце сортируем
d.sort()
print(d)