How to remove duplicates from a list with datatype checking?

Question

Python

there is this code

def clean_list(l):
result = []
for item in l:
if item not in result:
result.appent(item)
return result
only it doesn't distinguish float from int it doesn't reach me where to do type checking

Answer 1

If I understand the question correctly, then:

def clean_list(a):
    out = []
    for im in a:
        tmp = [im, type(im)]
        if not tmp in out:
            out.append(tmp)
    return [x[0] for x in out]


print(clean_list([1, 1, 2.0, 2, 2.0, 3, 1, 2, 3.0, 3.0, 2.0, 4, 4.0, 3.0]))

[1, 2.0, 2, 3, 3.0, 4, 4.0]

Answer 2

clean_list = lambda l: list(set(l))

Answer 3

1. What was wrong with set()?
2. ?
def clean_list(l):
result = []
for item in l:
if int(item) not in result:
result.appent(int(item))
return result

Answer 4

unique_as_tuple = dict.fromkeys([(num, type(num)) for num in values_list])
unique_as_numbers = [num for num, num_type in unique_as_tuple]