How to remove a number along with adjacent characters with a regular expression?

Question

Python

When parsing, I encountered duplication. I get the same items but with an insert somewhere in the string as '1st', '2nd', '3rd', '4th' and in different languages ​​like French '6ème'.
I know that you can remove numbers through a regular expression using '\d'.
How can I immediately remove everything that comes after the number before the space?
It is possible to go through the whole thing in a loop, but maybe there is a more elegant way?

Answer 1

re.sub(r'\d+\S+', '', text)