How to refer to a selector without specifying the name of the parent?

Question

Sass

Good afternoon.
The selector &--active &__show doesn't work :(

.filters {
    &--active .filters__show {
      display: none;
    }
}

Answer 1

Read about interpolation in Sass

.filters {
    $root: &;

    &--active #{$root}__show {
      display: none;
    }
}