How to properly parse data from bs4 ResultSet?

Question

Python

Good day.
Using the following line I get a ResultSet:

abc = soup.findAll('script', text = re.compile('Data'))

The resulting ResultSet itself:

[<script type="text/javascript">
data = {"url":"haha.com", "id":"12345", "name":"haha",};
... function() {abc.devg....})'
...

From all this, the goal is to extract the parameters in data, namely, let's say the url and id values.
There are no ideas how to do it. Tried various parsing options with soup and what is given above is the closest to the desired option.
I would be grateful for any advice.

Answer 1

I did not have time to test it 100%, the laptop was discharged. I'm writing from my phone.

import re
import json
from ast import literal_eval

pattern = re.compile(r'data[= ]+(?P<dict>.*);')
raw = pattern.search(s).groupdict()

# if валидый JSON
j = json.loads(raw['dict'])
print(j['id'], j['url'])
# запасной вариант
# elif похоже на валидный python-dict
d = literal_eval(raw['dict'])
print(d['id'], d['url'])

upd: answer updated

Answer 2

soup -
lazha lxml
and concretize tasks - search for substrings or what?